C++の練習を兼ねて, AtCoder Grand Contest 004 の 問題C (AND Grid) を解いてみた.
■感想.
1. 方針が見えなかったので, 解説を参照して実装したところ, 何とか, AC版となった.
2. 個人的には, 非常に面白い問題に感じた.
3. 時間を見つけて, 引き続き, 過去問を振り返っていきたいと思う.
本家のサイトAGC 004 解説をご覧下さい.
■C++版プログラム(問題C／AC版).
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// 解き直し. // https://img.atcoder.jp/data/agc/004/editorial.pdf #include <bits/stdc++.h> using namespace std; #define repex(i, a, b, c) for(int i = a; i < b; i += c) #define repx(i, a, b) repex(i, a, b, 1) #define rep(i, n) repx(i, 0, n) #define repr(i, a, b) for(int i = a; i >= b; i--) int board[555][555], r[555][555], b[555][555]; int main(){ // 1. 入力情報. int H, W; scanf("%d %d", &H, &W); rep(i, H){ char c[555]; scanf("%s", c); rep(j, W) if(c[j] == '#') board[i][j] = 1; // 紫色. } // 2. 事前準備 および 紫色箇所を, 赤色, 青色 で 着色. rep(i, H){ rep(j, W){ // 1列目 … 赤色. if(j == 0) r[i][j] = 1; // W列目 … 青色. if(j == W - 1) b[i][j] = 1; // それ以外 … 赤色 もしくは 青色. if(j > 0 && j < W - 1){ if(i & 1){ b[i][j] = 1; // 紫色あれば赤色も着色. if(board[i][j]) r[i][j] = 1; }else{ r[i][j] = 1; // 紫色あれば青色も着色. if(board[i][j]) b[i][j] = 1; } } } } // 3. 出力. rep(i, H){ rep(j, W) printf("%c", (r[i][j]) ? '#' : '.'); puts(""); } puts(""); rep(i, H){ rep(j, W) printf("%c", (b[i][j]) ? '#' : '.'); puts(""); } return 0; } |
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■参照サイト
AtCoder Grand Contest 004